F(x)=6x^2-10

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Solution for F(x)=6x^2-10 equation:



(F)=6F^2-10
We move all terms to the left:
(F)-(6F^2-10)=0
We get rid of parentheses
-6F^2+F+10=0
a = -6; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·(-6)·10
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{241}}{2*-6}=\frac{-1-\sqrt{241}}{-12} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{241}}{2*-6}=\frac{-1+\sqrt{241}}{-12} $

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